In Lisp, a function is a list that starts with lambda, a
byte-code function compiled from such a list, or alternatively a
primitive subr-object; names are “extra.” Although functions are
usually defined with defun and given names at the same time, it
is occasionally more concise to use an explicit lambda expression—an
anonymous function. Such a list is valid wherever a function name is.
Any method of creating such a list makes a valid function. Even this:
(setq silly (append '(lambda (x)) (list (list '+ (* 3 4) 'x))))
⇒ (lambda (x) (+ 12 x))
This computes a list that looks like (lambda (x) (+ 12 x)) and
makes it the value (not the function definition!) of
silly.
Here is how we might call this function:
(funcall silly 1)
⇒ 13
It does not work to write (silly 1), because this
function is not the function definition of silly. We
have not given silly any function definition, just a value as a
variable.
Most of the time, anonymous functions are constants that appear in
your program. For instance, you might want to pass one as an argument
to the function mapcar, which applies any given function to
each element of a list (see Mapping Functions).
See describe-symbols example, for a realistic example of this.
In the following example, we define a change-property
function that takes a function as its third argument, followed by a
double-property function that makes use of
change-property by passing it an anonymous function:
(defun change-property (symbol prop function)
(let ((value (get symbol prop)))
(put symbol prop (funcall function value))))
(defun double-property (symbol prop)
(change-property symbol prop (lambda (x) (* 2 x))))
In the double-property function, we did not quote the
lambda form. This is permissible, because a lambda form
is self-quoting: evaluating the form yields the form itself.
Whether or not you quote a lambda form makes a difference if
you compile the code (see Byte Compilation). If the lambda
form is unquoted, as in the above example, the anonymous function is
also compiled. Suppose, however, that we quoted the lambda
form:
(defun double-property (symbol prop)
(change-property symbol prop '(lambda (x) (* 2 x))))
If you compile this, the argument passed to change-property is
the precise list shown:
(lambda (x) (* x 2))
The Lisp compiler cannot assume this list is a function, even though
it looks like one, since it does not know what change-property
will do with the list. Perhaps it will check whether the car of
the third element is the symbol *!
The function special form explicitly tells the byte-compiler
that its argument is a function:
This special form returns function-object without evaluating it. In this, it is equivalent to
quote. However, it serves as a note to the Emacs Lisp compiler that function-object is intended to be used only as a function, and therefore can safely be compiled. Contrast this withquote, in Quoting.
The read syntax #' is a short-hand for using function.
Generally, it is not necessary to use either #' or
function; just use an unquoted lambda form instead.
(Actually, lambda is a macro defined using function.)
The following forms are all equivalent:
#'(lambda (x) (* x x))
(function (lambda (x) (* x x)))
(lambda (x) (* x x))
We sometimes write function instead of quote when
quoting the name of a function, but this usage is just a sort of
comment:
(function symbol) == (quote symbol) == 'symbol